2/3+d+1=16-d

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Solution for 2/3+d+1=16-d equation:



2/3+d+1=16-d
We move all terms to the left:
2/3+d+1-(16-d)=0
We add all the numbers together, and all the variables
d-(-1d+16)+1+2/3=0
We get rid of parentheses
d+1d-16+1+2/3=0
We multiply all the terms by the denominator
d*3+1d*3+2-16*3+1*3=0
We add all the numbers together, and all the variables
d*3+1d*3-43=0
Wy multiply elements
3d+3d-43=0
We add all the numbers together, and all the variables
6d-43=0
We move all terms containing d to the left, all other terms to the right
6d=43
d=43/6
d=7+1/6

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