2/3+x+2/5=(x+3)/5

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Solution for 2/3+x+2/5=(x+3)/5 equation:


x in (-oo:+oo)

x+2/3+2/5 = (x+3)/5 // - (x+3)/5

x-((x+3)/5)+2/3+2/5 = 0

(-1*(x+3))/5+x+2/3+2/5 = 0

(-1*3*(x+3))/(3*5)+(3*5*x)/(3*5)+(2*5)/(3*5)+(2*3)/(3*5) = 0

3*5*x-1*3*(x+3)+2*5+2*3 = 0

12*x-9+6+10 = 0

12*x+1+6 = 0

12*x+7 = 0

(12*x+7)/(3*5) = 0

(12*x+7)/(3*5) = 0 // * 3*5

12*x+7 = 0

12*x+7 = 0 // - 7

12*x = -7 // : 12

x = -7/12

x = -7/12

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