2/3+x=(5x-1)/5-6

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Solution for 2/3+x=(5x-1)/5-6 equation: 


x in (-oo:+oo)

x+2/3 = (5*x-1)/5-6 // - (5*x-1)/5-6

x-((5*x-1)/5)+2/3+6 = 0

(-1*(5*x-1))/5+x+2/3+6 = 0

(-1*3*(5*x-1))/(3*5)+(3*5*x)/(3*5)+(2*5)/(3*5)+(3*5*6)/(3*5) = 0

3*5*x-1*3*(5*x-1)+2*5+3*5*6 = 0

3+10+90 = 0

13+90 = 0

103 = 0

103/(3*5) = 0

103/(3*5) = 0 // * 3*5

103 = 0

x belongs to the empty set

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