2/3-(k+1/2)=1/6(k-51)

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Solution for 2/3-(k+1/2)=1/6(k-51) equation: 


k in (-oo:+oo)

2/3-k-(1/2) = (1/6)*(k-51) // - (1/6)*(k-51)

2/3-((1/6)*(k-51))-k-(1/2) = 0

(-1/6)*(k-51)-k+2/3-1/2 = 0

2/3-1/6*(k-51)-k-1/2 = 0

(-1/6*2*3*(k-51))/(2*3)+(2*3*(-k))/(2*3)+(2^2)/(2*3)+(-1*3)/(2*3) = 0

2*3*(-k)-1/6*2*3*(k-51)-1*3+4 = 0

4-7*k-3+51 = 0

55-7*k-3 = 0

52-7*k = 0

(52-7*k)/(2*3) = 0

(52-7*k)/(2*3) = 0 // * 2*3

52-7*k = 0

52-7*k = 0 // - 52

-7*k = -52 // : -7

k = -52/(-7)

k = 52/7

k = 52/7

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