2/3-9/b=4

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Solution for 2/3-9/b=4 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

2/3-(9/b) = 4 // - 4

2/3-(9/b)-4 = 0

2/3-9*b^-1-4 = 0

-9*b^-1 = 10/3 // : -9

b^-1 = -10/27

-1 < 0

1/(b^1) = -10/27 // * b^1

1 = -10/27*b^1 // : -10/27

-27/10 = b^1

b = -27/10

b = -27/10

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