2/3=(3x-6)/(4x+17)

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Solution for 2/3=(3x-6)/(4x+17) equation: 



2/3=(3x-6)/(4x+17)

We move all terms to the left:

2/3-((3x-6)/(4x+17))=0



Domain of the equation: (4x+17))!=0

x∈R



We calculate fractions


(-((3x-6)*3)/12x+8x/12x=0

We can not solve this equation

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