2/3=3/2(4-9x+3)

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Solution for 2/3=3/2(4-9x+3) equation:



2/3=3/2(4-9x+3)
We move all terms to the left:
2/3-(3/2(4-9x+3))=0
Domain of the equation: 2(4-9x+3))!=0
x∈R
We add all the numbers together, and all the variables
-(3/2(-9x+7))+2/3=0
We calculate fractions
()/(-54x)+(4x(-)/(-54x)=0
We calculate terms in parentheses: +(4x(-)/(-54x), so:
4x(-)/(-54x
We add all the numbers together, and all the variables
4x0/(-54x
We multiply all the terms by the denominator
4x0
We add all the numbers together, and all the variables
4x
Back to the equation:
+(4x)
We add all the numbers together, and all the variables
4x+()/(-54x)=0
We multiply all the terms by the denominator
4x*(-54x)+()=0
We add all the numbers together, and all the variables
4x*(-54x)=0
We multiply parentheses
-216x^2=0
a = -216; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-216)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-432}=0$

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