2/3X-7=11,x=

Solution for 2/3X-7=11,x= equation:

2/3X-7=11.X=

We move all terms to the left:

2/3X-7-(11.X)=0


Domain of the equation: 3X!=0

X!=0/3

X!=0

X∈R


We add all the numbers together, and all the variables

2/3X-(+11.X)-7=0

We get rid of parentheses

2/3X-11.X-7=0

We multiply all the terms by the denominator


-(11.X)*3X-7*3X+2=0

We add all the numbers together, and all the variables

-(+11.X)*3X-7*3X+2=0

We multiply parentheses

-33X^2-7*3X+2=0

Wy multiply elements

-33X^2-21X+2=0

a = -33; b = -21; c = +2;
Δ = b2-4ac
Δ = -212-4·(-33)·2
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{705}}{2*-33}=\frac{21-\sqrt{705}}{-66}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{705}}{2*-33}=\frac{21+\sqrt{705}}{-66}
$