2/3a+2=1/3(4a=1)

Solution for 2/3a+2=1/3(4a=1) equation:

2/3a+2=1/3(4a=1)

We move all terms to the left:

2/3a+2-(1/3(4a)=0


Domain of the equation: 3a!=0

a!=0/3

a!=0

a∈R



Domain of the equation: 34a+2!=0

We move all terms containing a to the left, all other terms to the right

34a!=-2

a!=-2/34

a!=-1/17

a∈R


We calculate fractions


(68a+2)/(102a^2+2)+(-(1*3a)/(102a^2+2)=0


We calculate terms in parentheses: +(-(1*3a)/(102a^2+2), so:

-(1*3a)/(102a^2+2

We add all the numbers together, and all the variables

-(+1*3a)/(102a^2+2

We multiply all the terms by the denominator


-(+1*3a)

We get rid of parentheses

-1*3a

Wy multiply elements

-3a

Back to the equation:

+(-3a)


We get rid of parentheses

(68a+2)/(102a^2+2)-3a=0

We multiply all the terms by the denominator


(68a+2)-3a*(102a^2+2)=0

We multiply parentheses

-306a^3+(68a+2)-6a=0

We get rid of parentheses

-306a^3+68a-6a+2=0

We do not support eapression: a^3