2/3b+19=35

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Solution for 2/3b+19=35 equation: 



2/3b+19=35

We move all terms to the left:

2/3b+19-(35)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

2/3b-16=0

We multiply all the terms by the denominator


-16*3b+2=0

Wy multiply elements

-48b+2=0

We move all terms containing b to the left, all other terms to the right

-48b=-2

b=-2/-48

b=1/24

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