2/3b+5=-1/3b-4

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Solution for 2/3b+5=-1/3b-4 equation: 



2/3b+5=-1/3b-4

We move all terms to the left:

2/3b+5-(-1/3b-4)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R





Domain of the equation: 3b-4)!=0

b∈R



We get rid of parentheses

2/3b+1/3b+4+5=0

We multiply all the terms by the denominator


4*3b+5*3b+2+1=0

We add all the numbers together, and all the variables

4*3b+5*3b+3=0

Wy multiply elements

12b+15b+3=0

We add all the numbers together, and all the variables

27b+3=0

We move all terms containing b to the left, all other terms to the right

27b=-3

b=-3/27

b=-1/9

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