2/3b+5=20

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Solution for 2/3b+5=20 equation: 



2/3b+5=20

We move all terms to the left:

2/3b+5-(20)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

2/3b-15=0

We multiply all the terms by the denominator


-15*3b+2=0

Wy multiply elements

-45b+2=0

We move all terms containing b to the left, all other terms to the right

-45b=-2

b=-2/-45

b=2/45

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