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2/3b+5=20)
We move all terms to the left:
2/3b+5-(20))=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
2/3b=0
We multiply all the terms by the denominator
2!=0
There is no solution for this equation
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