2/3b+5=20b

Solution for 2/3b+5=20b equation:

2/3b+5=20b

We move all terms to the left:

2/3b+5-(20b)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We add all the numbers together, and all the variables

-20b+2/3b+5=0

We multiply all the terms by the denominator


-20b*3b+5*3b+2=0

Wy multiply elements

-60b^2+15b+2=0

a = -60; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·(-60)·2
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{705}}{2*-60}=\frac{-15-\sqrt{705}}{-120}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{705}}{2*-60}=\frac{-15+\sqrt{705}}{-120}
$