2/3b+b+45+90+2b+90+b=540

Solution for 2/3b+b+45+90+2b+90+b=540 equation:

2/3b+b+45+90+2b+90+b=540

We move all terms to the left:

2/3b+b+45+90+2b+90+b-(540)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We add all the numbers together, and all the variables

4b+2/3b-315=0

We multiply all the terms by the denominator


4b*3b-315*3b+2=0

Wy multiply elements

12b^2-945b+2=0

a = 12; b = -945; c = +2;
Δ = b2-4ac
Δ = -9452-4·12·2
Δ = 892929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-945)-\sqrt{892929}}{2*12}=\frac{945-\sqrt{892929}}{24}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-945)+\sqrt{892929}}{2*12}=\frac{945+\sqrt{892929}}{24}
$