2/3b-1/3b+12=26

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Solution for 2/3b-1/3b+12=26 equation: 



2/3b-1/3b+12=26

We move all terms to the left:

2/3b-1/3b+12-(26)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

2/3b-1/3b-14=0

We multiply all the terms by the denominator


-14*3b+2-1=0

We add all the numbers together, and all the variables

-14*3b+1=0

Wy multiply elements

-42b+1=0

We move all terms containing b to the left, all other terms to the right

-42b=-1

b=-1/-42

b=1/42

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