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(2/3)*b-(5*a) = (5/12)*b // - (5/12)*b
(2/3)*b-(5*a)-((5/12)*b) = 0
(2/3)*b-5*a+(-5/12)*b = 0
1/4*b-5*a = 0
x naleu017Cy do R
x in (-oo:+oo)
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