2/3b=5

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Solution for 2/3b=5 equation: 



2/3b=5

We move all terms to the left:

2/3b-(5)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We multiply all the terms by the denominator


-5*3b+2=0

Wy multiply elements

-15b+2=0

We move all terms containing b to the left, all other terms to the right

-15b=-2

b=-2/-15

b=2/15

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