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2/3b=5/6b
We move all terms to the left:
2/3b-(5/6b)=0
Domain of the equation: 3b!=0
b!=0/3
b!=0
b∈R
Domain of the equation: 6b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
2/3b-(+5/6b)=0
We get rid of parentheses
2/3b-5/6b=0
We calculate fractions
12b/18b^2+(-15b)/18b^2=0
We multiply all the terms by the denominator
12b+(-15b)=0
We get rid of parentheses
12b-15b=0
We add all the numbers together, and all the variables
-3b=0
b=0/-3
b=0
Równanie nie ma rozwiązania
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