2/3c+6=-10

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Solution for 2/3c+6=-10 equation:



2/3c+6=-10
We move all terms to the left:
2/3c+6-(-10)=0
Domain of the equation: 3c!=0
c!=0/3
c!=0
c∈R
We add all the numbers together, and all the variables
2/3c+16=0
We multiply all the terms by the denominator
16*3c+2=0
Wy multiply elements
48c+2=0
We move all terms containing c to the left, all other terms to the right
48c=-2
c=-2/48
c=-1/24

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