2/3c+9=12

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Solution for 2/3c+9=12 equation: 



2/3c+9=12

We move all terms to the left:

2/3c+9-(12)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



We add all the numbers together, and all the variables

2/3c-3=0

We multiply all the terms by the denominator


-3*3c+2=0

Wy multiply elements

-9c+2=0

We move all terms containing c to the left, all other terms to the right

-9c=-2

c=-2/-9

c=2/9

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