2/3c-11=4+4/7c

Solution for 2/3c-11=4+4/7c equation:

2/3c-11=4+4/7c

We move all terms to the left:

2/3c-11-(4+4/7c)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 7c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

2/3c-(4/7c+4)-11=0

We get rid of parentheses

2/3c-4/7c-4-11=0

We calculate fractions


14c/21c^2+(-12c)/21c^2-4-11=0

We add all the numbers together, and all the variables

14c/21c^2+(-12c)/21c^2-15=0

We multiply all the terms by the denominator


14c+(-12c)-15*21c^2=0

Wy multiply elements

-315c^2+14c+(-12c)=0

We get rid of parentheses

-315c^2+14c-12c=0

We add all the numbers together, and all the variables

-315c^2+2c=0

a = -315; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-315)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-315}=\frac{-4}{-630}
=2/315
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-315}=\frac{0}{-630}
=0
$