2/3c-3+5/4c=-c+5/2c+2

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Solution for 2/3c-3+5/4c=-c+5/2c+2 equation: 



2/3c-3+5/4c=-c+5/2c+2

We move all terms to the left:

2/3c-3+5/4c-(-c+5/2c+2)=0



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R





Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R





Domain of the equation: 2c+2)!=0

c∈R



We add all the numbers together, and all the variables

2/3c+5/4c-(-1c+5/2c+2)-3=0

We get rid of parentheses

2/3c+5/4c+1c-5/2c-2-3=0

We calculate fractions

We do not support ecpression: c^3

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