2/3d+3=109/15-2/5d

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Solution for 2/3d+3=109/15-2/5d equation: 


d in (-oo:+oo)

(2/3)*d+3 = 109/15-((2/5)*d) // - 109/15-((2/5)*d)

(2/3)*d+(2/5)*d-(109/15)+3 = 0

(2/3)*d+(2/5)*d-109/15+3 = 0

16/15*d-64/15 = 0 // + 64/15

16/15*d = 64/15 // : 16/15

d = 64/15/16/15

d = 4

d = 4

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