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2/3d-3/5d=4
We move all terms to the left:
2/3d-3/5d-(4)=0
Domain of the equation: 3d!=0
d!=0/3
d!=0
d∈R
Domain of the equation: 5d!=0We calculate fractions
d!=0/5
d!=0
d∈R
10d/15d^2+(-9d)/15d^2-4=0
We multiply all the terms by the denominator
10d+(-9d)-4*15d^2=0
Wy multiply elements
-60d^2+10d+(-9d)=0
We get rid of parentheses
-60d^2+10d-9d=0
We add all the numbers together, and all the variables
-60d^2+d=0
a = -60; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-60)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-60}=\frac{-2}{-120} =1/60 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-60}=\frac{0}{-120} =0 $
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