2/3f+1=5

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Solution for 2/3f+1=5 equation: 



2/3f+1=5

We move all terms to the left:

2/3f+1-(5)=0



Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R



We add all the numbers together, and all the variables

2/3f-4=0

We multiply all the terms by the denominator


-4*3f+2=0

Wy multiply elements

-12f+2=0

We move all terms containing f to the left, all other terms to the right

-12f=-2

f=-2/-12

f=1/6

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