2/3f-5=7

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Solution for 2/3f-5=7 equation: 



2/3f-5=7

We move all terms to the left:

2/3f-5-(7)=0



Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R



We add all the numbers together, and all the variables

2/3f-12=0

We multiply all the terms by the denominator


-12*3f+2=0

Wy multiply elements

-36f+2=0

We move all terms containing f to the left, all other terms to the right

-36f=-2

f=-2/-36

f=1/18

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