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2/3g+1/4g=22
We move all terms to the left:
2/3g+1/4g-(22)=0
Domain of the equation: 3g!=0
g!=0/3
g!=0
g∈R
Domain of the equation: 4g!=0We calculate fractions
g!=0/4
g!=0
g∈R
8g/12g^2+3g/12g^2-22=0
We multiply all the terms by the denominator
8g+3g-22*12g^2=0
We add all the numbers together, and all the variables
11g-22*12g^2=0
Wy multiply elements
-264g^2+11g=0
a = -264; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-264)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-264}=\frac{-22}{-528} =1/24 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-264}=\frac{0}{-528} =0 $
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