2/3h+12=18

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Solution for 2/3h+12=18 equation: 



2/3h+12=18

We move all terms to the left:

2/3h+12-(18)=0



Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



We add all the numbers together, and all the variables

2/3h-6=0

We multiply all the terms by the denominator


-6*3h+2=0

Wy multiply elements

-18h+2=0

We move all terms containing h to the left, all other terms to the right

-18h=-2

h=-2/-18

h=1/9

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