2/3h+5=17

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Solution for 2/3h+5=17 equation: 



2/3h+5=17

We move all terms to the left:

2/3h+5-(17)=0



Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



We add all the numbers together, and all the variables

2/3h-12=0

We multiply all the terms by the denominator


-12*3h+2=0

Wy multiply elements

-36h+2=0

We move all terms containing h to the left, all other terms to the right

-36h=-2

h=-2/-36

h=1/18

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