2/3h-1/3h*11=8

Solution for 2/3h-1/3h*11=8 equation:

2/3h-1/3h*11=8

We move all terms to the left:

2/3h-1/3h*11-(8)=0


Domain of the equation: 3h!=0

h!=0/3

h!=0

h∈R



Domain of the equation: 3h*11!=0

h!=0/1

h!=0

h∈R


We calculate fractions


66h/99h^2+(-3h)/99h^2-8=0

We multiply all the terms by the denominator


66h+(-3h)-8*99h^2=0

Wy multiply elements

-792h^2+66h+(-3h)=0

We get rid of parentheses

-792h^2+66h-3h=0

We add all the numbers together, and all the variables

-792h^2+63h=0

a = -792; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-792)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-792}=\frac{-126}{-1584}
=7/88
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-792}=\frac{0}{-1584}
=0
$