2/3j=3/2(j+3)

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Solution for 2/3j=3/2(j+3) equation: 



2/3j=3/2(j+3)

We move all terms to the left:

2/3j-(3/2(j+3))=0



Domain of the equation: 3j!=0

j!=0/3

j!=0

j∈R





Domain of the equation: 2(j+3))!=0

j∈R



We calculate fractions


(4jj/(6j^2j+(-(3*3j)/(6j^2j=0

We can not solve this equation

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