2/3k+3/2=29/6+2k

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Solution for 2/3k+3/2=29/6+2k equation: 



2/3k+3/2=29/6+2k

We move all terms to the left:

2/3k+3/2-(29/6+2k)=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R





Domain of the equation: 6+2k)!=0

We move all terms containing k to the left, all other terms to the right

2k)!=-6

k!=-6/1

k!=-6

k∈R



We add all the numbers together, and all the variables

2/3k-(+2k+29/6)+3/2=0

We get rid of parentheses

2/3k-2k-29/6+3/2=0

We calculate fractions

There is no solution for this equation

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