2/3k+5=11

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Solution for 2/3k+5=11 equation: 



2/3k+5=11

We move all terms to the left:

2/3k+5-(11)=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R



We add all the numbers together, and all the variables

2/3k-6=0

We multiply all the terms by the denominator


-6*3k+2=0

Wy multiply elements

-18k+2=0

We move all terms containing k to the left, all other terms to the right

-18k=-2

k=-2/-18

k=1/9

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