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2/3k-(k+1/2)=1/6(k+1)
We move all terms to the left:
2/3k-(k+1/2)-(1/6(k+1))=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 6(k+1))!=0We add all the numbers together, and all the variables
k∈R
2/3k-(+k+1/2)-(1/6(k+1))=0
We get rid of parentheses
2/3k-k-(1/6(k+1))-1/2=0
We calculate fractions
(24kk/(36k^2k+(-(1*3k*2)/(36k^2k+(-108k^2)/(36k^2k-k=0
We can not solve this equation
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