2/3k-(k+1/2)=1/6(k+2)

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Solution for 2/3k-(k+1/2)=1/6(k+2) equation: 



2/3k-(k+1/2)=1/6(k+2)

We move all terms to the left:

2/3k-(k+1/2)-(1/6(k+2))=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R





Domain of the equation: 6(k+2))!=0

k∈R



We add all the numbers together, and all the variables

2/3k-(+k+1/2)-(1/6(k+2))=0

We get rid of parentheses

2/3k-k-(1/6(k+2))-1/2=0

We calculate fractions


(24kk/(36k^2k+(-(1*3k*2)/(36k^2k+(-108k^2)/(36k^2k-k=0

We can not solve this equation

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