2/3k-(k+1/2)=1/6(k-51)

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Solution for 2/3k-(k+1/2)=1/6(k-51) equation: 


k in (-oo:+oo)

(2/3)*k-k-(1/2) = (1/6)*(k-51) // - (1/6)*(k-51)

(2/3)*k-((1/6)*(k-51))-k-(1/2) = 0

(-1/6)*(k-51)+(2/3)*k-k-1/2 = 0

(2*k)/3-1/6*(k-51)-k-1/2 = 0

(-1/6*2*3*(k-51))/(2*3)+(2*2*k)/(2*3)+(2*3*(-k))/(2*3)+(-1*3)/(2*3) = 0

2*2*k-1/6*2*3*(k-51)+2*3*(-k)-1*3 = 0

3*k-6*k-3+51 = 0

51-3*k-3 = 0

48-3*k = 0

(48-3*k)/(2*3) = 0

(48-3*k)/(2*3) = 0 // * 2*3

48-3*k = 0

48-3*k = 0 // - 48

-3*k = -48 // : -3

k = -48/(-3)

k = 16

k = 16

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