2/3k-(k+1/3)=1/9(k+1)

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Solution for 2/3k-(k+1/3)=1/9(k+1) equation: 



2/3k-(k+1/3)=1/9(k+1)

We move all terms to the left:

2/3k-(k+1/3)-(1/9(k+1))=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R





Domain of the equation: 9(k+1))!=0

k∈R



We add all the numbers together, and all the variables

2/3k-(+k+1/3)-(1/9(k+1))=0

We get rid of parentheses

2/3k-k-(1/9(k+1))-1/3=0

We calculate fractions


-k+(18kk/(81k^2k+(-(1*3k*3)/(81k^2k+(-9kk/(81k^2k=0

We can not solve this equation

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