2/3k-(k+1/3)=1/9(k+3)

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Solution for 2/3k-(k+1/3)=1/9(k+3) equation: 


k in (-oo:+oo)

(2/3)*k-k-(1/3) = (1/9)*(k+3) // - (1/9)*(k+3)

(2/3)*k-((1/9)*(k+3))-k-(1/3) = 0

(-1/9)*(k+3)+(2/3)*k-k-1/3 = 0

(2*k)/3-1/9*(k+3)-k-1/3 = 0

(-1/9*3*(k+3))/3+(2*k)/3+(3*(-k))/3-1/3 = 0

2*k-1/9*3*(k+3)+3*(-k)-1 = 0

5/3*k-3*k-1-1 = 0

-4/3*k-1-1 = 0

-4/3*k-2 = 0

(-4/3*k-2)/3 = 0

(-4/3*k-2)/3 = 0 // * 3

-4/3*k-2 = 0

-4/3*k-2 = 0 // + 2

-4/3*k = 2 // : -4/3

k = 2/(-4/3)

k = -3/2

k = -3/2

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