2/3k-(k-1-2)=1/6(k-51)

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Solution for 2/3k-(k-1-2)=1/6(k-51) equation: 


k in (-oo:+oo)

(2/3)*k-k+1+2 = (1/6)*(k-51) // - (1/6)*(k-51)

(2/3)*k-((1/6)*(k-51))-k+1+2 = 0

(-1/6)*(k-51)+(2/3)*k-k+1+2 = 0

(2*k)/3-1/6*(k-51)-k+1+2 = 0

(-1/6*3*(k-51))/3+(2*k)/3+(3*(-k))/3+(1*3)/3+(2*3)/3 = 0

2*k-1/6*3*(k-51)+3*(-k)+1*3+2*3 = 0

3/2*k-3*k+3+6+51/2 = 0

3-3/2*k+6+51/2 = 0

6-3/2*k+57/2 = 0

69/2-3/2*k = 0

(69/2-3/2*k)/3 = 0

(69/2-3/2*k)/3 = 0 // * 3

69/2-3/2*k = 0

69/2-3/2*k = 0 // - 69/2

-3/2*k = -69/2 // : -3/2

k = -69/2/(-3/2)

k = 23

k = 23

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