2/3m+1/4m=25

Solution for 2/3m+1/4m=25 equation:

2/3m+1/4m=25

We move all terms to the left:

2/3m+1/4m-(25)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We calculate fractions


8m/12m^2+3m/12m^2-25=0

We multiply all the terms by the denominator


8m+3m-25*12m^2=0

We add all the numbers together, and all the variables

11m-25*12m^2=0

Wy multiply elements

-300m^2+11m=0

a = -300; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-300)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-300}=\frac{-22}{-600}
=11/300
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-300}=\frac{0}{-600}
=0
$