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2/3m-2/5m=4
We move all terms to the left:
2/3m-2/5m-(4)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 5m!=0We calculate fractions
m!=0/5
m!=0
m∈R
10m/15m^2+(-6m)/15m^2-4=0
We multiply all the terms by the denominator
10m+(-6m)-4*15m^2=0
Wy multiply elements
-60m^2+10m+(-6m)=0
We get rid of parentheses
-60m^2+10m-6m=0
We add all the numbers together, and all the variables
-60m^2+4m=0
a = -60; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-60)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-60}=\frac{-8}{-120} =1/15 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-60}=\frac{0}{-120} =0 $
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