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2/3n+25=n
We move all terms to the left:
2/3n+25-(n)=0
Domain of the equation: 3n!=0We add all the numbers together, and all the variables
n!=0/3
n!=0
n∈R
-1n+2/3n+25=0
We multiply all the terms by the denominator
-1n*3n+25*3n+2=0
Wy multiply elements
-3n^2+75n+2=0
a = -3; b = 75; c = +2;
Δ = b2-4ac
Δ = 752-4·(-3)·2
Δ = 5649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5649}}{2*-3}=\frac{-75-\sqrt{5649}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5649}}{2*-3}=\frac{-75+\sqrt{5649}}{-6} $
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