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2/3n-1=2/9n-4
We move all terms to the left:
2/3n-1-(2/9n-4)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 9n-4)!=0We get rid of parentheses
n∈R
2/3n-2/9n+4-1=0
We calculate fractions
18n/27n^2+(-6n)/27n^2+4-1=0
We add all the numbers together, and all the variables
18n/27n^2+(-6n)/27n^2+3=0
We multiply all the terms by the denominator
18n+(-6n)+3*27n^2=0
Wy multiply elements
81n^2+18n+(-6n)=0
We get rid of parentheses
81n^2+18n-6n=0
We add all the numbers together, and all the variables
81n^2+12n=0
a = 81; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·81·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*81}=\frac{-24}{162} =-4/27 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*81}=\frac{0}{162} =0 $
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