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n in (-oo:+oo)
(2/3)*n = 4*n-((10/3)*n)-(1/2) // - 4*n-((10/3)*n)-(1/2)
(2/3)*n-(4*n)+(10/3)*n+1/2 = 0
(2/3)*n-4*n+(10/3)*n+1/2 = 0
1/2 = 0
n belongs to the empty set
n belongs to the empty set
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