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2/3n=4n-10/3n-12
We move all terms to the left:
2/3n-(4n-10/3n-12)=0
Domain of the equation: 3n!=0
n!=0/3
n!=0
n∈R
Domain of the equation: 3n-12)!=0We get rid of parentheses
n∈R
2/3n-4n+10/3n+12=0
We multiply all the terms by the denominator
-4n*3n+12*3n+2+10=0
We add all the numbers together, and all the variables
-4n*3n+12*3n+12=0
Wy multiply elements
-12n^2+36n+12=0
a = -12; b = 36; c = +12;
Δ = b2-4ac
Δ = 362-4·(-12)·12
Δ = 1872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1872}=\sqrt{144*13}=\sqrt{144}*\sqrt{13}=12\sqrt{13}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{13}}{2*-12}=\frac{-36-12\sqrt{13}}{-24} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{13}}{2*-12}=\frac{-36+12\sqrt{13}}{-24} $
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