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2/3p-24=-2p
We move all terms to the left:
2/3p-24-(-2p)=0
Domain of the equation: 3p!=0We get rid of parentheses
p!=0/3
p!=0
p∈R
2/3p+2p-24=0
We multiply all the terms by the denominator
2p*3p-24*3p+2=0
Wy multiply elements
6p^2-72p+2=0
a = 6; b = -72; c = +2;
Δ = b2-4ac
Δ = -722-4·6·2
Δ = 5136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5136}=\sqrt{16*321}=\sqrt{16}*\sqrt{321}=4\sqrt{321}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-4\sqrt{321}}{2*6}=\frac{72-4\sqrt{321}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+4\sqrt{321}}{2*6}=\frac{72+4\sqrt{321}}{12} $
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