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2/3p-3/5=1/2p+1
We move all terms to the left:
2/3p-3/5-(1/2p+1)=0
Domain of the equation: 3p!=0
p!=0/3
p!=0
p∈R
Domain of the equation: 2p+1)!=0We get rid of parentheses
p∈R
2/3p-1/2p-1-3/5=0
We calculate fractions
(-36p^2)/150p^2+100p/150p^2+(-75p)/150p^2-1=0
We multiply all the terms by the denominator
(-36p^2)+100p+(-75p)-1*150p^2=0
Wy multiply elements
(-36p^2)-150p^2+100p+(-75p)=0
We get rid of parentheses
-36p^2-150p^2+100p-75p=0
We add all the numbers together, and all the variables
-186p^2+25p=0
a = -186; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-186)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-186}=\frac{-50}{-372} =25/186 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-186}=\frac{0}{-372} =0 $
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