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2/3p-3/5p=8
We move all terms to the left:
2/3p-3/5p-(8)=0
Domain of the equation: 3p!=0
p!=0/3
p!=0
p∈R
Domain of the equation: 5p!=0We calculate fractions
p!=0/5
p!=0
p∈R
10p/15p^2+(-9p)/15p^2-8=0
We multiply all the terms by the denominator
10p+(-9p)-8*15p^2=0
Wy multiply elements
-120p^2+10p+(-9p)=0
We get rid of parentheses
-120p^2+10p-9p=0
We add all the numbers together, and all the variables
-120p^2+p=0
a = -120; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-120)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-120}=\frac{-2}{-240} =1/120 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-120}=\frac{0}{-240} =0 $
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