2/3r-4=16+2r

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Solution for 2/3r-4=16+2r equation:



2/3r-4=16+2r
We move all terms to the left:
2/3r-4-(16+2r)=0
Domain of the equation: 3r!=0
r!=0/3
r!=0
r∈R
We add all the numbers together, and all the variables
2/3r-(2r+16)-4=0
We get rid of parentheses
2/3r-2r-16-4=0
We multiply all the terms by the denominator
-2r*3r-16*3r-4*3r+2=0
Wy multiply elements
-6r^2-48r-12r+2=0
We add all the numbers together, and all the variables
-6r^2-60r+2=0
a = -6; b = -60; c = +2;
Δ = b2-4ac
Δ = -602-4·(-6)·2
Δ = 3648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3648}=\sqrt{64*57}=\sqrt{64}*\sqrt{57}=8\sqrt{57}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-8\sqrt{57}}{2*-6}=\frac{60-8\sqrt{57}}{-12} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+8\sqrt{57}}{2*-6}=\frac{60+8\sqrt{57}}{-12} $

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